demerphq wrote:
x=y; but x,x != y,y?but ratherx=y, but x,x != y,z
But if we say x=y and x=z can we then say that x,x != y,z If say $x = []; $y = []; $z = []; is_deeply($x, $y); # passes is_deeply($x, $z): # passes is_deeply([$x,$x], [$y, $z]); # fails for some reason If we broke this out into a formal logical proof, the only way that x,x != y,z would would is if x != y or x != z, or both. -- Michael Peters Developer Plus Three, LP
