matt diephouse wrote:
$junction = $x | $y | $z; foo($junction); # Call foo($x), foo($y), and foo($z) # in parallel and collect the results # in a disjunction
Looking at that code, I'm wondering how you pass a junction. Suppose I want to pass a junction to a subroutine instead of calling the sub with each value of the junction... how would I do that?
Tell the sub that it's expecting an undistributed junction as its argument:
sub foo($param is junction) {...}
Damian
