At 9:05 AM +1100 11/19/02, Damian Conway wrote:
Hrm. What happens if the junction is then used as an iterator?matt diephouse wrote:$junction = $x | $y | $z; foo($junction); # Call foo($x), foo($y), and foo($z) # in parallel and collect the results # in a disjunction
Looking at that code, I'm wondering how you pass a junction. Suppose I want to pass a junction to a subroutine instead of calling the sub with each value of the junction... how would I do that?
Tell the sub that it's expecting an undistributed junction as its argument:
$junction = File::Open("foo") | File::Open("bar);
for (<$junction>) {
...
}
Which could get interesting if inside the for loop the code creates more junctions and iterates over them. (Potentially ad infinitum)
And here I thought Quantum INTERCAL was a joke... :)
--
Dan
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