At 11:11 AM 8/9/00 -0700, Larry Wall wrote:
>Dan Sugalski writes:
>: Does that mean, then, that when module A does a "$C::bar = 1" it affects a
>: different package namespace than module B doing a "$C::bar = 2"?
>
>Presumably.
Hmmmm. That brings up some issues of ambiguity, then. If you use C in
package A, and also in package B, which do you see when you're in main and
access $C::bar?
>: And does it also extend to things like this:
>:
>: package A;
>: use C 1.2;
>: package B;
>: use C 1.4;
>:
>: where two packages in the same file use different versions of module C and
>: get them?
>
>I expect that could also be made to work, provided the semantics of
>importation remain package-scoped and don't become lexically scoped.
Sure. They'd have to be, otherwise packages split across different files
would get a rather bizarre view of the world. This sort of means we'll need
some sort of two-level stash, one per-package and one global. (Unless
you're outlawing symbolic references... :)
>To me, it really just means that the *real* name of the package includes
>the implementation (author?) and version, but that when you say
>
> use C;
>
>you're just choosing to wildcard both the implementation and version.
>This view says that we probably ought to figure out how to encode the
>implementation and version syntactically as part of the package name,
>rather than as a 3rd argument to use.
Yup. I can see the build procedures needing to know this too, since we'll
probably need to give modules with shared libraries unique names. Some
platforms (OS/2 and VMS, at least) will need that, as they get cranky if
you try and load shareables with the same base filename.
>Think about the long names of fonts for an example of how far this
>can be taken.
Would this be "Taken to its logical and sensible conclusion" or "Taken as
far as it can possibly go, though it you turn around and look *really* hard
with binoculars you can see where you crossed the line, way back there by
the horizon"?
Dan
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