--- Brent Dax <[EMAIL PROTECTED]> wrote: > Buddha Buck: > # How would you parse: > # > # @a = @b[[5]]; > > A 2D array slice, since you can't hyper numbers? >
It's hypering the [5].
@a = a list made up of the [5] (sub-)element of each element of @b.
for @b -> @b_subarr { @a.push(@b_subarr[5]); }
=Austin
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