> 30 сент. 2019 г., в 22:29, Tomas Vondra <tomas.von...@2ndquadrant.com> 
> написал(а):
> 
> On Mon, Sep 30, 2019 at 09:20:22PM +0500, Andrey Borodin wrote:
>> 
>> 
>>> 30 сент. 2019 г., в 20:56, Tomas Vondra <tomas.von...@2ndquadrant.com> 
>>> написал(а):
>>> 
>>> I mean this:
>>> 
>>>  /*
>>>   * Use int64 to prevent overflow during calculation.
>>>   */
>>>  compressed_size = (int32) ((int64) rawsize * 9 + 8) / 8;
>>> 
>>> I'm not very familiar with pglz internals, but I'm a bit puzzled by
>>> this. My first instinct was to compare it to this:
>>> 
>>>  #define PGLZ_MAX_OUTPUT(_dlen)     ((_dlen) + 4)
>>> 
>>> but clearly that's a very different (much simpler) formula. So why
>>> shouldn't pglz_maximum_compressed_size simply use this macro?
> 
>> 
>> compressed_size accounts for possible increase of size during
>> compression. pglz can consume up to 1 control byte for each 8 bytes of
>> data in worst case.
> 
> OK, but does that actually translate in to the formula? We essentially
> need to count 8-byte chunks in raw data, and multiply that by 9. Which
> gives us something like
> 
>  nchunks = ((rawsize + 7) / 8) * 9;
> 
> which is not quite what the patch does.

I'm afraid neither formula is correct, but all this is hair-splitting 
differences.

Your formula does not account for the fact that we may not need all bytes from 
last chunk.
Consider desired decompressed size of 3 bytes. We may need 1 control byte and 3 
literals, 4 bytes total
But nchunks = 9.

Binguo's formula is appending 1 control bit per data byte and one extra control 
byte.
Consider size = 8 bytes. We need 1 control byte, 8 literals, 9 total.
But compressed_size = 10.

Mathematically correct formula is
compressed_size = (int32) ((int64) rawsize * 9 + 7) / 8;
Here we take one bit for each data byte, and 7 control bits for overflow.

But this equations make no big difference, each formula is safe. I'd pick one 
which is easier to understand and document (IMO, its nchunks = ((rawsize + 7) / 
8) * 9).

Thanks!

--
Andrey Borodin
Open source RDBMS development team leader
Yandex.Cloud



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