Re: [PHP] How to access a program outside of PHP?

[Raditha Dissanayake]

hi
Backticks is simply the ` sign (usually the character above the tab). 
Popularly know as `hair on the ear` in my country :-)
for example if you want to invoke ls from php you just type

$result = `ls`;

hey presto the output from ls is now in your $result variable.

all the best

Adam Douglas wrote:

1) When I echo out $szPipe I get "Resource id #2".

     

Sorry i was thinking of backticks.  btw have you tried it ? 
(backticks)
   

Backticks? Is this a PHP API function, I can't find it? That's the thing
here I haven't been able to get things to work and I have no clue what I
should use, exec(), system(), popen(), etc. gs just needs to be run, I do
not require any output back from it other than if I can determine if it's
been ran or not (true/false).
 

3)Yes I tried running gs in the console as root works fine 
     

and as myself and
   

that works fine. The user is www that runs httpd. How could 
     

I test to see if
   

www has access? To my understanding such accounts can not be 
     

used to log in
   

with. I have chown the /htdocs/ to be www:wwww.

     

can't login yes. but you can try: sudo -u www /htdocs/gs
   

Okay, tried that and yes it worked.

Any more ideas? Is there any logs I could look at to find out more, I've
looked around but haven't found anything as of yet.
 



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