Re: [PHP] How to access a program outside of PHP?

[Raditha Dissanayake]

btw have you checked if you are in safe_mode? in php.ini
error level can also be set in php.ini
my guess is that you have a problem in your chroot setup.

best regards

Adam Douglas wrote:

Mmm... okay. I tried that and nothing. Is there no way for me to determine
what the problem is? Error message some place, log file, etc? I do not
understand why this is not work. Even a simple example from the PHP manual
on system() does not work.
 

I meant to do this:

$szPipe = `/htdocs/gs -q
-dNOPAUSE -dBATCH -sDEVICE=pdfwrite
-sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf
/htdocs/Sep08-113523.pdf`;
   

Backticks is simply the ` sign (usually the character above 
       

the tab). 
   

Popularly know as `hair on the ear` in my country :-)
for example if you want to invoke ls from php you just type
$result = `ls`;

hey presto the output from ls is now in your $result variable.
  

       

Ohhh okay. Well if you mean to do this, $szPipe = 
     

popen(`/htdocs/gs -q
   

-dNOPAUSE -dBATCH -sDEVICE=pdfwrite
-sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf
/htdocs/Sep08-113523.pdf`, "r");. This does not seem change 
     

anything. If I
   

do this with the system() example, I get "Warning: system(): 
     

Cannot execute
   

a blank command in /htdocs/index.php on line 14".
     

 



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