Thank you!! It worked!!
The wrong sample was 'dot'11'dot'abcd, but
the first dot was not shown properly...
And, now I have another problem:
In fact, the input strings are lines from a webpage, and
they sometimes have line-feed as in:
11.abcd.32.efgh.54.ij <--here
kh.41.lmno. <--here
63.pqrs
And, with ereg_replace("(\.)([0-9])","\\1<br><br>\\2",$string),
the result I expect is:
11.abcd.
32.efgh.
54.ijkh.
41.lmno.
63.pqrs.
But, the actual result is:
11.abcd.
32.efgh.
54.ij <-- problem
kh.
41.lmno.
63.pqrs. <-- problem
I tried some more regular expressions to solve this, but
they don work yet.
So, please help me~~
Thank you in advance.
Joshua
----- Original Message -----
From: "Kelly Hallman" <[EMAIL PROTECTED]>
To: "Joshua" <[EMAIL PROTECTED]>
Cc: "PHP General list" <[EMAIL PROTECTED]>
Sent: Saturday, December 27, 2003 1:27 PM
Subject: Re: [PHP] Regular Expression
> On Sat, 27 Dec 2003, Joshua wrote:
> > I'm trying to change the string, for example,
> >
> > $string = "11.abcd.32.efgh.53.ijk";
> > to
> >
> > 11.abcd.
> > 32.efgh.
> > 53.ijk.
> >
> > with ereg_replace. Like
> > ereg_replace("\.[0-9]","<BR>",$string);
> > How can I recover the original characters after replacing them with <BR>
> > in ereg_replace?
> >
> > ereg_replace("\.[0-9]","<BR>\\0",$string) gives me the
> > wrong result like:
> >
> > 11.abcd.
> > 32.efgh.
> > 53.ijk.
>
> Since the output you want and the output you didn't want are identical in
> your post, it was hard to tell what you were trying to do, but...
>
> I think this is what you want..
> ereg_replace("(\.)([0-9])","\\1<br>\\2",$string);
> (minus the last decimal point, missing from your original string)
>
> --
> Kelly Hallman
> // Ultrafancy
>
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