create table oras(
Name VARCHAR(30),
TimeIn DATETIME,
TimeOut DATETIME,
Total DATETIME
);
insert into oras values('Nhadie','2004-10-10 10:10:00','2004-11-11
12:12:00','TIMEDIFF(TimeIn,TImeOut)');
Hi,
Are those correct? Because the value on the Total field is 000-00-00
00:00:00.
I think there's something wrong. I'm using 4.0.
mysql> select * from oras;
+--------+---------------------+---------------------+------------------
---+
| Name | TimeIn | TimeOut | Total
|
+--------+---------------------+---------------------+------------------
---+
| Nhadie | 2004-10-10 10:10:00 | 2004-11-11 12:12:00 | 0000-00-00
00:00:00 |
+--------+---------------------+---------------------+------------------
---+
1 row in set (0.01 sec)
TIA
-----Original Message-----
From: Justin Patrin [mailto:[EMAIL PROTECTED]
Sent: Thursday, February 12, 2004 9:08 AM
To: [EMAIL PROTECTED]
Subject: [PHP] Re: I think this is a mysql question
Ronald Ramos wrote:
> How can I use PHP to compute the difference between two dates(with
> time)? Let's say in mysql, I have field 1, login, and on field 2, I
> have logout.
>
> How can I compute the diffrence between login and logut and output it
> on field 3 let's say totaltime.
>
> Is this a mysql question? Or can PHP actually do this?
>
> TIA
Both can do it, but it depends heavily on what type of date format it
is. If it's a normal mysql date or datetime (not a timestamp) then you
can grab it, then do:
$seconds = strtotime($field1) - strtotime($field2);
strtotime() does a good job of converting just about every type of
formatted date.
If you're using a timestamp, there aren't any deliminators. I'm not sure
if strtotime() will parse those as you want. In this case (and the
other, actually) you can easily use SQL.
SELECT UNIX_TIMESTAMP(field1) - UNIX_TIMESTAMP(field2) AS secondsBetween
FROM table
--
paperCrane <Justin Patrin>
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