If you only want to replace strings, then drop the regular expression functions! (a
common mistake)
Use for example str_replace, or in this case, strtr which is better because it accepts
an array as replacement pattern.
For example:
$foo = array("foo" => "apple", "bar" => "banana");
$string = "I like foos and bars";
$string = strtr($string, $foo);
echo $string;
output:
I like apples and bananas
// Victor
----- Original Message -----
From: "'Nick Wilson'" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, January 12, 2002 1:17 PM
Subject: Re: [PHP] multiple replaces...
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>
> * On 12-01-02 at 13:02
> * Lauri Vain said....
>
> > Hi Nick,
> >
> > Yes, I thought about that. But, what should I do when the markers are absolutely
>NOT in any sequence.
> >
> > I also thought about something like
> > $replace[1][1] = "!one!"; //marker
> > $replace[1][2] = "hehee"; //replace with
> > $replace[1][1] = "test"; //marker
> > $replace[1][2] = "foobar"; //replace with
> > $replace[1][1] = "repl"; //marker
> > $replace[1][2] = "humpty-dumpty"; //replace with
> > $replace[1][1] = "blah"; //marker
> > $replace[1][2] = "boo"; //replace with
> >
> > Now, when I would do a loop thingie that goes through all those, then it would be
>a pretty nice and compact solution...
> >
> > What about speed issues regarding this solution?
>
> I don't think speed will be an issue unless you have thousands of
> markers, in which case you'll need to re-think the whole thing.
>
> Can you not put all of your markers in an array like
>
> $markers=array("m1", "m2", "m_whatever");
>
> and all your replacements likewise
>
> $replace=array("r1", "r2", "r_whatever");
>
> and then loop through like that?
>
> If not, explain a little more about the context of the problem and let's
> see if we can come up with an alternative.
> - --
>
> Nick Wilson
>
> Tel: +45 3325 0688
> Fax: +45 3325 0677
> Web: www.explodingnet.com
>
>
>
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