On Wed, Jul 10, 2002 at 12:14:58PM -0700, Fargo Lee wrote:
>
> This suggests, as do a few posts I just noticed in the manual, that
> one cannot assign the output of system() and perhaps passthru() and exec()
> to a variable.
I forgot to mention, that's not accurate. I just ran a test to make sure.
Got the results just fine.
Just for clarity, here's my test (PHP 4.2.1, NT 4.0):
# real directory.
# result: output shows file list, false no, return 0
# $output = system('dir c:\books', $return_var);
# fake directory.
# result: output shows nothing, false yes, return 1
$output = system('dir y:\fake', $return_var);
echo "output: $output";
echo '<hr />';
echo 'output false? ' . ( ($output == FALSE) ? 'yes' : 'no' );
echo '<hr />';
echo "return: $return_var";
--Dan
I think this is only possible using backticks, which I can't
> use as this needs to be run in safe mode. So I guess I just need to use the
> return_var as you suggested. Thanks!
>
> "Analysis & Solutions" <[EMAIL PROTECTED]> wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > On Tue, Jul 09, 2002 at 11:41:47PM -0700, Fargo Lee wrote:
> >
> > > got it to assign a 0 (success) or 1 (failure) to the return_var argument
> as
> > > you suggested so I am happy.
> >
> > Good!
> >
> >
> > > What mixed me up and I still don't understand is the manual entry for
> > > system() says ...
> > >
> > > "Returns the last line of the command output on success, and FALSE on
> > > failure."
> > >
> > > When it says it "Returns", where does it return this information and how
> can
> > > it be captured for comparison?
> >
> > The thing that's tripping you up is, I believe, executing MySQL programs
> > at a prompt doesn't produce any visible output. But, if you executed a
> > command that returns some output to STDOUT, like "ls", you'd see the last
> > line of output therefrom in the "Return."
> >
> > --Dan
> >
> > --
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>
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