Thanks Elias, I took a look at the code and there are indeed many things to learn; however, it's all in js. I'm trying to have php write the js, but I don't know enough about arrays and manipulating their elements.
Roger -----Original Message----- From: lallous [mailto:[EMAIL PROTECTED]] Sent: Wednesday, September 11, 2002 2:02 AM To: [EMAIL PROTECTED] Subject: [PHP] Re: Dependent Dropdown Boxes Hi, Try to learn many things from the test code i created below: http://lgwm.org/ozone/dynatable.htm Good luck, Elias "Roger Lewis" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > The Situation: > > I'm trying to create a pair of dynamic dropdown boxes where the options in > the second box are dependent on the selection in the first box. I call the > first box "categories" and the second, "subcategories". I want to store the > categories and subcategories in a mysql table(s) so that a user can > dynamically update them. Currently, I have a single table called > categories, with columns: id, category, and subcategory. > > The primary code for selecting the options for the second box is in > javascript. This code makes use of the following datasets for storing the > various categories and subcategories. If I can get php to generate this > text, then the dependent boxes will work. > > datasets=new Array(); > datasets[0]="Category1,subCategory1_1,subCategory1_2,subCategory1_3,subCateg > ory1_4".split(","); > datasets[1]="Category2,subCategory2_1,subCategory2_2,subCategory2_3".split(" > ,"); > datasets[2]="Category3,subCategory3_1, subCategory3_2, > subCategory3_3,subCategory3_4,subCategory3_5".split(","); > datasets[3]="Category4,subCategory4_1,subCategory4_2,subCategory4_3,subCateg > ory4_4".split(","); > datasets[4]="Category5,subCategory5_1,subCategory5_2,subCategory5_3,subCateg > ory5_4,subCategory5_5,subCategory5_6".split(","); > etc. > > The Problem: > > Using the following code I can get php to print the results, but only in a > line-by-line, category/subcategory format. Of course, this is NOT what is > needed. Each subcategory name should be on the same line as its associated > category. > > <?php > $dbConnect = mysql_connect("localhost", "root", "pwd"); > mysql_select_db("new_kb",$dbConnect); > $sql = "SELECT * from categories"; > $result = mysql_query($sql); > for ($count = 1; $row = mysql_fetch_row ($result); ++$count) > { > print "<br>datasets[$count]=\""; > print "$row[1],"; > print "$row[2]\""; > } > ?> > > > datasets[0]="Category1,subCategory1_1 > datasets[1]="Category1,subCategory1_2 > datasets[2]="Category1,subCategory1_3 > datasets[3]="Category1,subCategory1_4 > datasets[4]="Category2,subCategory2_1 > datasets[5]="Category2,subCategory2_2 > etc. > > Can someone explain how to write the php code to output the category and > subcategory names from the mysql table to match the javascript format above. > > Thanks in advance for any help or suggestions. > > Roger Lewis > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
