>> I am new to php and that the folowing error: Warning:
mysql_num_rows():
>> supplied argument is not a valid MySQL result resource in
>> /home/tbonestu/public_html/smallimages.php
>>
>> i dont know what i am doing wrong here is the code:
>>
>> @ $db = mysql_pconnect(connect info);
>>
>> mysql_select_db("images");
>> $query = "select * from images where type =".$type.""; $result =
>> mysql_query($query); $num_results = mysql_num_rows($result);
>That generally means your query failed. Try to echo mysql_error() after
your query to see what the problem is. You probably need quotes around $type
or $type has no value.
You also have too many quotes on the $query line, try echoing your $query
variable to see if it reads properly.
Mark
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
