Hi Nick, > I am new to php and that the folowing error: > Warning: mysql_num_rows(): supplied argument > is not a valid MySQL result resource in > /home/tbonestu/public_html/smallimages.php > > i dont know what i am doing wrong here is the code: > > @ $db = mysql_pconnect(connect info);
Along with the other suggestions to check your $query variable, you should change this line to : $db = @mysql_pconnect($whatever); The @ goes in front of the function call, not the variable, if you want to suppress any potential error messages generated by the function. Cheers Jon -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php