I have a file. I'll paste from line 32 to 34 <? ..... $sql = "select USUARIO from docente where USUARIO = '$usuario'"; $result = mysql_query($sql, $link); if (mysql_num_rows($result) == 1) { // line 34 .... ?>
I get the next warning: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/olimpiad/public_html/base/alta1.php on line 34 I'm running the script on a linux server. could someone help me. Thank you. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php