If the browser still doesn't listen, you can always put a time() arg in you 
img src. ie. "<img src=\"image.gif?" . time() . "\">"

David Erickson wrote:

> I had a similar problem and I just put this in front of my php so
> everytime my scripts are called they always tell the browser and any proxy
> servers not to cache anything from me.
> 
> 
> header("Expires: Mon, 26 Jul 1997 05:00:00 GMT");    // Date in the past
> header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT");
>                                                      // always modified
> header("Cache-Control: no-store, no-cache, must-revalidate");  // HTTP/1.1
> header("Cache-Control: post-check=0, pre-check=0", false);
> header("Pragma: no-cache");                          // HTTP/1.0
> 
> 
> ----- Original Message -----
> From: "Donahue Ben" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Wednesday, October 09, 2002 1:00 PM
> Subject: [PHP] Image problem
> 
> 
>> I upload an image.  Once I upload this image using the
>> is_uploaded_file function, then writing this image
>> file using the copy function.  Everything seems to
>> work fine.  When i try to update (that is uploading a
>> new file and saving it with the same name as the first
>> file created) it shows the first image instead of the
>> second image.  So what I did was closed my browser,
>> then reopened it, then everything was ok.  So I figure
>> that I have a cache problem.  I then tried using the
>> clearstatcache() function right after I update this
>> image file.  But it did not seem to work.  So am I
>> going to have to close and reopen my browser to see
>> these changes take place or is there something else I
>> can do?
>>
>> Ben
>>
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-- 
Cheers,

Owen Prime
http://www.noggin.com.au

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