My inclination is that it is correct in enforcing that the obverse of
the obverse is the original function. I'm open to good reasons why this
isn't always the case, but I think if you need to break this rule, then
what you're looking for probably isn't the obverse. Using &. in this
case will just complicate the code.

Marshall

On Sun, Nov 04, 2012 at 10:17:37PM -0500, Henry Rich wrote:
> Yes, that seems wrong.  It should be
> 
> i. :.+
> 
> shouldn't it?
> 
> Henry Rich
> 
> On 11/4/2012 10:15 PM, km wrote:
> >Henry, what do you make of
> >
> >    i. :. (i. :. +) b. _1
> >i. :.+ :.i.
> >
> >?
> >
> >Kip Murray
> >
> >Sent from my iPad
> >
> >
> >On Nov 4, 2012, at 5:45 PM, Henry Rich <henryhr...@nc.rr.com> wrote:
> >
> >>   i. :. (i. :. +) ^:_1 ^:_1 ]5
> >>0 1 2 3 4
> >>
> >>The obverse of i. :. (i. :. +) should be (i. :. +), and
> >>the obverse of that should be + .  I think.  But it isn't.
> >>
> >>Henry Rich
> >>----------------------------------------------------------------------
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> >----------------------------------------------------------------------
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