Yes, that is the concise explanation. And, as Marshall says, it's
probably better that way. It certainly makes my current project easier
if that is so.
Henry Rich
On 11/5/2012 12:13 AM, km wrote:
It appears the obverse of u :. v is v :. u and not simply v . This explains
the behavior Henry saw.
Kip Murray
Sent from my iPad
On Nov 4, 2012, at 9:33 PM, Marshall Lochbaum <mwlochb...@gmail.com> wrote:
My inclination is that it is correct in enforcing that the obverse of
the obverse is the original function. I'm open to good reasons why this
isn't always the case, but I think if you need to break this rule, then
what you're looking for probably isn't the obverse. Using &. in this
case will just complicate the code.
Marshall
On Sun, Nov 04, 2012 at 10:17:37PM -0500, Henry Rich wrote:
Yes, that seems wrong. It should be
i. :.+
shouldn't it?
Henry Rich
On 11/4/2012 10:15 PM, km wrote:
Henry, what do you make of
i. :. (i. :. +) b. _1
i. :.+ :.i.
?
Kip Murray
Sent from my iPad
On Nov 4, 2012, at 5:45 PM, Henry Rich <henryhr...@nc.rr.com> wrote:
i. :. (i. :. +) ^:_1 ^:_1 ]5
0 1 2 3 4
The obverse of i. :. (i. :. +) should be (i. :. +), and
the obverse of that should be + . I think. But it isn't.
Henry Rich
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