What is the problem here?
(ic-:ic2)&> 1j2 0j2
1 1
([:(ic-:ic2)>) 1j2 0j2
0
u@v y ↔ u v y Moreover, the monadic uses of u@v and u&v are equivalent.
Linda
-----Original Message-----
From: [email protected] [mailto:programming-
[email protected]] On Behalf Of David Ward Lambert
Sent: Monday, January 21, 2013 10:45 AM
To: programming
Subject: Re: [Jprogramming] [Jprogrammingou Hermitian from triangular
Interrupting may be a bad idea.
NB. -------- Use 13 : correctly.
NB. f=: 13 :',j./&i:/+.y' NB. no.
NB. f=: 13 : '([: , j./&i:/@+.) y' NB. yes.
ic2 =: [: , j./&i:/@+.
NB. Using a proverb is as if its definition
NB. were inserted with parenthesis.
NB. Copy ic2 definition verbatim,
NB. Surround with parentheses.
NB. Put in the arguments, then fix quotes.
13 : '([: , j./&i:/@+.) y'
[: , j./&i:/@+.
NB. The definition was tacit,
NB. 13 : returns this tacit verb unchanged
NB. -------- Equivalence of ic and ic2
NB."However, I do not understand how ic and ic2 agree when they don't!"
ic =: [: , ([: i: 9&o.) j./ [: i: 11&o.
ic2 =: [: , j./&i:/@+.
NB. ic and ic2 are identical at rank 0
(ic -: ic2)&>1j2 0j2
1 1
([: < ic)"0 ] 1j2 0j2
+----------------------------------------------------------------+----------
---------+
|_1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2|0j_2
0j_1 0 0j1 0j2|
+----------------------------------------------------------------+----------
---------+
([: < ic2)"0 ] 1j2 0j2
+----------------------------------------------------------------+----------
---------+
|_1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2|0j_2
0j_1 0 0j1 0j2|
+----------------------------------------------------------------+----------
---------+
>Date: Mon, 21 Jan 2013 03:58:24 -0500
>From: "Linda Alvord" <[email protected]>
>To: <[email protected]>
>Subject: Re: [Jprogramming] [Jprogrammingou Hermitian from triangular
>Message-ID: <001d01cdf7b5$78a4cd20$69ee6760$@net>
>Content-Type: text/plain; charset="koi8-r"
>
>Since this has a mistake it is hard to reconstruct what I did wrong.
This
>represents what I was doing:
>
>
>
> ic2=: [: , j./&i:/@+.
>
> ic2
>
>[: , j./&i:/@+.
>
> ([: , j./&i:/@+.)2
>
>_2 _1 0 1 2
>
> f=: 13 :',j./&i:/+.y'
>................
>
> ic 1j2 0j2
>
>_1j_2 _1j_1 _1 _1j1 _1j2 _1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2
0j_2
>0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2 1j_2 1j_1 1 1j1 1j2 0j_2 0j_1 0 0j1
0j2
>0j_2 0j_1 0 0j1 0j2 0j_2 0j_1 0 0j1 0j2 0j_2 0j_1 0 0j1 0j2 0j_2 0j_1 0
0j1
>0j2 0j_2 0j_1 0 0j1 0j2
>
>
>
> ic2 1j2 0j2
>
>_1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2 0j_2
0j_1 0
>0j1 0j2 0 0 0 0 0 0 0 0 0 0
>
>
>
> (ic-:ic2)&>1j2 0j2
>
>1 1
>
>
>
>However, I do not understand how ic and ic2 agree when they don't!
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
----------------------------------------------------------------------
For information about J forums see http://www.jsoftware.com/forums.htm
