Linda, rank is saying "Gotcha again!" --Kip
(ic-:ic2)&> b. 0
0 0 0
([:(ic-:ic2)>) b. 0
_ _ _
Sent from my iPad
On Jan 22, 2013, at 12:28 AM, "Linda Alvord" <[email protected]> wrote:
> What is the problem here?
>
> (ic-:ic2)&> 1j2 0j2
> 1 1
> ([:(ic-:ic2)>) 1j2 0j2
> 0
>
> u@v y ↔ u v y Moreover, the monadic uses of u@v and u&v are equivalent.
>
> Linda
>
> -----Original Message-----
> From: [email protected] [mailto:programming-
> [email protected]] On Behalf Of David Ward Lambert
> Sent: Monday, January 21, 2013 10:45 AM
> To: programming
> Subject: Re: [Jprogramming] [Jprogrammingou Hermitian from triangular
>
> Interrupting may be a bad idea.
>
> NB. -------- Use 13 : correctly.
> NB. f=: 13 :',j./&i:/+.y' NB. no.
> NB. f=: 13 : '([: , j./&i:/@+.) y' NB. yes.
>
> ic2 =: [: , j./&i:/@+.
>
> NB. Using a proverb is as if its definition
> NB. were inserted with parenthesis.
> NB. Copy ic2 definition verbatim,
> NB. Surround with parentheses.
> NB. Put in the arguments, then fix quotes.
>
> 13 : '([: , j./&i:/@+.) y'
> [: , j./&i:/@+.
>
> NB. The definition was tacit,
> NB. 13 : returns this tacit verb unchanged
>
>
>
> NB. -------- Equivalence of ic and ic2
> NB."However, I do not understand how ic and ic2 agree when they don't!"
>
> ic =: [: , ([: i: 9&o.) j./ [: i: 11&o.
>
> ic2 =: [: , j./&i:/@+.
>
> NB. ic and ic2 are identical at rank 0
> (ic -: ic2)&>1j2 0j2
> 1 1
>
> ([: < ic)"0 ] 1j2 0j2
> +----------------------------------------------------------------+----------
> ---------+
> |_1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2|0j_2
> 0j_1 0 0j1 0j2|
> +----------------------------------------------------------------+----------
> ---------+
> ([: < ic2)"0 ] 1j2 0j2
> +----------------------------------------------------------------+----------
> ---------+
> |_1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2|0j_2
> 0j_1 0 0j1 0j2|
> +----------------------------------------------------------------+----------
> ---------+
>
>
>
>> Date: Mon, 21 Jan 2013 03:58:24 -0500
>> From: "Linda Alvord" <[email protected]>
>> To: <[email protected]>
>> Subject: Re: [Jprogramming] [Jprogrammingou Hermitian from triangular
>> Message-ID: <001d01cdf7b5$78a4cd20$69ee6760$@net>
>> Content-Type: text/plain; charset="koi8-r"
>>
>> Since this has a mistake it is hard to reconstruct what I did wrong.
> This
>> represents what I was doing:
>>
>>
>>
>> ic2=: [: , j./&i:/@+.
>>
>> ic2
>>
>> [: , j./&i:/@+.
>>
>> ([: , j./&i:/@+.)2
>>
>> _2 _1 0 1 2
>>
>> f=: 13 :',j./&i:/+.y'
>> ................
>>
>> ic 1j2 0j2
>>
>> _1j_2 _1j_1 _1 _1j1 _1j2 _1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2
> 0j_2
>> 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2 1j_2 1j_1 1 1j1 1j2 0j_2 0j_1 0 0j1
> 0j2
>> 0j_2 0j_1 0 0j1 0j2 0j_2 0j_1 0 0j1 0j2 0j_2 0j_1 0 0j1 0j2 0j_2 0j_1 0
> 0j1
>> 0j2 0j_2 0j_1 0 0j1 0j2
>>
>>
>>
>> ic2 1j2 0j2
>>
>> _1j_2 _1j_1 _1 _1j1 _1j2 0j_2 0j_1 0 0j1 0j2 1j_2 1j_1 1 1j1 1j2 0j_2
> 0j_1 0
>> 0j1 0j2 0 0 0 0 0 0 0 0 0 0
>>
>>
>>
>> (ic-:ic2)&>1j2 0j2
>>
>> 1 1
>>
>>
>>
>> However, I do not understand how ic and ic2 agree when they don't!
>
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