05.07.18 01:51, Victor Stinner пише:
== Pattern 1, straighforward ==
while True:
line = input.readline()
if not line:
break
...
IMHO here assingment expression is appropriate here. The code remains
straighfoward to read.
while (line := input.readline()):
...
We already have an idiom for this:
for line in input:
...
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