On 2020-07-04 at 20:33:36 +0100,
Regarding "[Python-ideas] Re: Add builtin function for min(max()),"
Henk-Jaap Wagenaar <wagenaarhenkj...@gmail.com> wrote:
> On Sat, 4 Jul 2020 at 19:58, Christopher Barker <python...@gmail.com> wrote:
>
> > Hmm.
> >
> >
> > Since NaN is neither greater than nor less that anything, it seems the
> > only correct answer to any
> > Min,max,clamp involving a NaN is NaN.
> >
> >
> Simplifying the signature, in Python we have:
>
> def min(*iterable):
> iterator = iter(iterable)
> minimum = next(iterable)
> for item in iterator:
> if item < minimum:
> minimum = item
> return minimum
>
> Due to this, min(0, float('nan')) == 0 and same for max. I would hence
> expect clamp to behave similarly.
Yuck: We also have min(float('nan'), 0) == float('nan').
I'm not sure what I'd expect a hypothetical clamp function to do.
Someone with actual use cases will have more insight.
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