On Tue, Dec 22, 2020 at 5:59 AM David Mertz <me...@gnosis.cx> wrote:
>
> On Mon, Dec 21, 2020 at 6:32 PM Chris Angelico <ros...@gmail.com> wrote:
>>
>> But the real question is: Why do points compare equal based on their
>> locations, if you need them to be independently stored in a set?
>> Logically, if they are equal, the set either contains that one thing
>> or it doesn't.
>
>
> This is a 3 minute example, not a fleshed out application design.  The 
> intuition I was going for was that various places might be located at e.g. 
> lat/lon coordinates. But some are in the same building, hence equal address.  
> Using `==` as a way of comparing being in the same place could be useful.  
> Yes, I can also think of other ways of designing this (e.g. 
> `p1.sameAddress(p2)`).  My goal here was showing plausibility, not proposing 
> a specific software design for a given need.
>

Yeah, fair enough. But I asked it that way because figuring out an
answer to that question (which requires knowledge of the actual
use-case) would immediately answer the question of how to handle
hashing.

ChrisA
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