As far as I understand, it is not possible. Is it?
Something similar to:
var = 710
variable_name = [k for k, v in locals().items() if v == 710][0]
print("Your variable name is " + variable_name)
,except robust.
Possible ways to expose it:
* builtin function `varname(obj: object) —> str`
* object.__varname__ dunder (this one wouldn’t clutter general namespace)
I am working on some code and just got to the point where it seems I could make
use of it. The case is as follows:
# What I do now:
class A:
defaults = dict()
def set_default(self, a):
self.defaults['a'] = a
def make_something(self, a=None):
a = a if a is not None else self.defaults.get('a')
return Something(a)
# What I would like to be able to do:
class A:
defaults = dict()
def set_default(self, a):
self.defaults[a.__varname__] = a
def make_something(self, a=None):
a = a if a is not None else self.defaults.get(a.__varname__)
return Something(a)
In this case I like second one, because it allows a tight coupling of variable
names, which has the following benefits:
1. General simplification, where one doesn’t have to think variable name and
its key value in dictionary. Code looks cleaner.
2. If one was to change a variable name of `set_default` it would immediately
surface as an error.
3. For someone working with IDEs or making use of clever multiple selection
tools, it would be easy to change all in one go.
Any reasons why the above would not be a good practice?
Any reasons why exposing it is not a good idea?
Would this be difficult to achieve from python dev’s perspective?
— This one can’t be solved with deferred eval :/ —
Regards,
DG_______________________________________________
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