Please read the next part of my e-mail too. It actually answer your question.
> On 12 Sep 2023, at 13:00, Chris Angelico <ros...@gmail.com> wrote: > > On Tue, 12 Sept 2023 at 19:51, Dom Grigonis <dom.grigo...@gmail.com> wrote: >> >> It wouldn’t. I know this is weird and not in line of how things work. This >> is more about simply getting reference variable name in locals() from the >> reference itself. But how would one access the variable name, when once >> called it returns the object it points to, not itself. So this would >> obviously require an exception in parser itself. >> >> a = object() >> b = a >> print(a.__varname__) # ‘a' >> print(b.__varname__) # 'b' >> print((a + b).__varname__) # Undefined??? ‘a + b’? >> > > I don't understand your desired semantics. Do you just want to take > whatever is given and put it in quotes? > > ChrisA > _______________________________________________ > Python-ideas mailing list -- python-ideas@python.org > To unsubscribe send an email to python-ideas-le...@python.org > https://mail.python.org/mailman3/lists/python-ideas.python.org/ > Message archived at > https://mail.python.org/archives/list/python-ideas@python.org/message/ZWO3FPC2G2AWA5TNINBX4ZHDMKFBWQZN/ > Code of Conduct: http://python.org/psf/codeofconduct/ _______________________________________________ Python-ideas mailing list -- python-ideas@python.org To unsubscribe send an email to python-ideas-le...@python.org https://mail.python.org/mailman3/lists/python-ideas.python.org/ Message archived at https://mail.python.org/archives/list/python-ideas@python.org/message/U3R6MHLYKC6R7RX2LG7EACVLOPB6TH5N/ Code of Conduct: http://python.org/psf/codeofconduct/
