Yes, if `==` was replaced by `is`. Currently it is even more random as it would return the first one which evaluates __eq__() positively.As for the example in your first post: var = 710 variable_name = [k fork, v inlocals().items()ifv == 710][0] print("Your variable name is "+ variable_name)it does "work", but it doesn't make much sense with Python's semantics. You could have two identifiers bound to the same object; which one you got hold of would be essentially random.
I'm not sure what you're saying. In: var1 = 710 var2 = 710 variable_names = [k for k, v in locals().items() if v is 710]Depending on the Python implementation, variable_names may be ['var1', 'var2'] or it may be empty (depending on whether 710 is interned). It could also in theory contain one of 'var1', 'var2' but not the other, though I would be surprised if that happened in practice. The behaviour is not guaranteed and should not be relied on.
Rob Cliffe
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