def f(): a = 12 def g(): global a if a < 14: a=13 g() return a
print f() This function raises an error. Is there any way to access the a in f() from inside g(). I could find few past discussions on this subject, I could not find the simple answer whether it is possible to do this reference. - Suresh -- http://mail.python.org/mailman/listinfo/python-list