Ross Ridge <[EMAIL PROTECTED]> said:
> If you have Python 2.5, here's a faster version:
>
> from struct import *
> unpack_i32be = Struct(">l").unpack
>
> def from3Bytes_ross2(s):
> return unpack_i32be(s + "\0")[0] >> 8
Bob Greschke <[EMAIL PROTECTED]> wrote:
> That's not even intelligible. I wanna go back to COBOL. :)
It's the same as the previous version except that it "precompiles"
the struct.unpack() format string. It works similar to the way Python
handles regular expressions.
Ross Ridge
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db //
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