Re: 2's complement conversion. Is this right?

[Peter Otten]

Ivan Illarionov wrote:

> And even faster:
> a = array.array('i', '\0' + '\0'.join((s[i:i+3] for i in xrange(0,
> len(s), 3))))
> if sys.byteorder == 'little':
>     a.byteswap()
> 
> I think it's a fastest possible implementation in pure python

Clever, but note that it doesn't work correctly for negative numbers. For
those you'd have to prepend "\xff" instead of "\0".

Peter

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