All: Say I have an array: a = (['rrrrggggbbbbaaaa'],['rrrrggggbbbbaaaa']) How
do I make it so that I now have: starting with first element (a[0])new_arr[0] =
'r'new_arr[1] = 'g'new_arr[2] = 'b'new_arr[3] = 'a'new_arr[4] = 'r'.....
continuing "through" a[1] with the same new_arrnew_arr[N] = 'r'new_arr[N+1] =
'g'.... -M
From: [EMAIL PROTECTED]: [EMAIL PROTECTED]; [EMAIL PROTECTED]: RE:
numpy.frombuffer != unpack() ??Date: Fri, 16 May 2008 17:31:30 -0500
Thank you! That solved it! -M
> To: python-list@python.org> From: [EMAIL PROTECTED]> Subject: Re:
> numpy.frombuffer != unpack() ??> Date: Fri, 16 May 2008 17:25:00 -0500> >
> Marlin Rowley wrote:> > All:> > > > I'm getting different floating point
> values when I use numpy vs. unpack().> > > > frgba = numpy.frombuffer(<string
> of bytes>, dtype=float32)> > buffer = unpack("!f", byte)> > > > frgba[0] !=
> buffer[0]> > > > why? This is forcing me use the unpack() function since it's
> giving me > > the correct values. What am I doing wrong?> > Endianness,
> perhaps? '!' specifies big-endian data (an alias for '>'). Most > likely, you
> are on a little-endian platform. All of the dtypes in numpy default > to the
> native-endianness unless specified. If you want to read big-endian data >
> using numpy, do this:> > frgba = numpy.frombuffer(<string of bytes>,
> dtype='>f')> > If you have any more problems with numpy, please join us on
> the numpy mailing > list. When reporting problems, please try to provide a
> small but complete > snippet of self-contained code, the output that you got,
> and explain the output > that you expected to get. Thank you.> >
> http://www.scipy.org/Mailing_Lists> > -- > Robert Kern> > "I have come to
> believe that the whole world is an enigma, a harmless enigma> that is made
> terrible by our own mad attempt to interpret it as though it had> an
> underlying truth."> -- Umberto Eco> > -->
> http://mail.python.org/mailman/listinfo/python-list
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