On Fri, 24 Oct 2014 12:55:19 -0700 (PDT), sohcahto...@gmail.com wrote: >On Friday, October 24, 2014 12:36:23 PM UTC-7, Seymore4Head wrote: >> On Fri, 24 Oct 2014 12:25:33 -0700 (PDT), sohcahto...@gmail.com wrote: >> >> >On Friday, October 24, 2014 12:12:10 PM UTC-7, Seymore4Head wrote: >> >> On Fri, 24 Oct 2014 11:57:12 -0700 (PDT), sohcahto...@gmail.com wrote: >> >> >> >> >On Friday, October 24, 2014 11:17:53 AM UTC-7, Seymore4Head wrote: >> >> >> On Fri, 24 Oct 2014 11:52:15 -0600, Ian Kelly <ian.g.ke...@gmail.com> >> >> >> wrote: >> >> >> >> >> >> >On Fri, Oct 24, 2014 at 11:03 AM, Seymore4Head >> >> >> ><Seymore4Head@hotmail.invalid> wrote: >> >> >> >> Actually I was a little frustrated when I added that line back in as >> >> >> >> the other lines all work. >> >> >> >> Using list(range(10)) Doesn't throw an error but it doesn't work. >> >> >> >> >> >> >> >> http://i.imgur.com/DTc5zoL.jpg >> >> >> >> >> >> >> >> The interpreter. I don't know how to use that either. >> >> >> > >> >> >> >Try both of these in the interpreter, and observe the difference: >> >> >> > >> >> >> >7 in range(10) >> >> >> > >> >> >> >"7" in range(10) >> >> >> > >> >> >> >Do you understand what the difference between 7 and "7" is? >> >> >> >> >> >> I do understand that. 7 is a number and "7" is a string. >> >> >> What my question was...and still is...is why >> >> >> Python 3 fails when I try using >> >> >> y=1 800 get charter >> >> >> >> >> >> y in range str(range(10)) >> >> >> should work because y is a string and str(range(10)) should be >> >> >> "y" in str(1) fails. >> >> >> It doesn't give an error it's just not True when y is a number. >> >> >> >> >> >> These hints are just not working. I am too thick for hints. :) >> >> >> If you could use it in the code, I might understand. >> >> >> The other work arounds that were posted work. >> >> >> I have used them. str(range(10)) doesn't work. >> >> >> >> >> >> import string >> >> >> def nametonumber(name): >> >> >> lst=[] >> >> >> nx=[] >> >> >> digit=[] >> >> >> digit="".join(str(i) for i in range(10)) >> >> >> for x in name: >> >> >> lst.append(x) >> >> >> for y in (lst): >> >> >> if y in list(range(1,10)): >> >> >> #if y in "1234567890": >> >> >> #if y.isdigit(): >> >> >> #if y in digit: >> >> >> #if y in string.digits: >> >> >> nx.append(y) >> >> >> if y in " -()": >> >> >> nx.append(y) >> >> >> if y in "abc": >> >> >> nx.append("2") >> >> >> if y in "def": >> >> >> nx.append("3") >> >> >> if y in "ghi": >> >> >> nx.append("4") >> >> >> if y in "jkl": >> >> >> nx.append("5") >> >> >> if y in "mno": >> >> >> nx.append("6") >> >> >> if y in "pqrs": >> >> >> nx.append("7") >> >> >> if y in "tuv": >> >> >> nx.append("8") >> >> >> if y in "wxyz": >> >> >> nx.append("9") >> >> >> number="".join(e for e in nx) >> >> >> return number >> >> >> a="1-800-getcharter" >> >> >> print (nametonumber(a))#1800 438 2427 837 >> >> >> a="1-800-leo laporte" >> >> >> print (nametonumber(a)) >> >> >> a="1 800 dialaho" >> >> >> print (nametonumber(a)) >> >> >> >> >> >> Please >> >> > >> >> >Your code here is actually pretty close to a correct answer. Just a few >> >> >things to consider... >> >> > >> >> >- Why are you converting your name string to a list? It is unnecessary. >> >> > When you do "for y in <some string>", then y will still be single >> >> >characters on each iteration of the loop. >> >> > >> >> >- "if y in string.digits" should work fine. >> >> > >> >> >- "if y in list(range(1,10)" won't work for two reasons: First, it >> >> >creates a list of numbers, not strings. Second, even if it did, it >> >> >would be missing the "0" digit. >> >> > >> >> >- At the end, when you convert your list to a string, you don't need to >> >> >use list comprehension, since nx is already a list. number = >> >> >"".join(nx) should work fine. >> >> > >> >> >Also, in general, you need to stop and slow down and think like a >> >> >programmer. If you get an error, your instinct shouldn't be to just >> >> >hack at it to make the error go away. Look at the error and try to make >> >> >sense of it. Learn what the error means and try to fix the core problem. >> >> > >> >> >And for @#$%'s sake...stop saying "It isn't working" and not >> >> >elaborating. You've been told by every other post in this thread to >> >> >show us what you did and what the error was. You've also been told to >> >> >*NOT* retype what you see and to copy/paste your code and the error >> >> >because when you make a typo when copying, we might see a problem that >> >> >doesn't exist and then you just get more confused. >> >> >> >> Ok I think I may have the question you guys are looking for. >> >> I just posted it. >> >> See above. >> >> >> >> But it's still broke. :( >> > >> >str(range(10)) doesn't do what you think it does. >> > >> >Run 'print(str(range(10)))' and look at what you get. >> >> Yeah, I know that. My question is why? >> The answer was that Python 3 only stores the min and max values but >> you can still iterate over them. >> I don't think that means what I think it means. > >"You can iterate over them" pretty much just means you can use them as the >source of a 'for' loop. But in your case, when you're calling 'for y in >str(range(10))', you're not using 'range(10)' as the source of your loop, >you're using the result of a str() function call, and you're calling str() on >range(), which doesn't return a concrete value in Python 3. If you try to >print a range(), you're just getting a string containing your original call to >range. > >And that's why you're seeing the 1 and a in your output. str(range(10)) >returns the string 'range(10)'. > >Like I said in a previous post, use 'string.digits'. Try this test code and >see what you get: > >import string >name="123-xyz-abc" >print("string.digits is", string.digits) >for x in name: > if x in range(10): > print ("Range",(x)) > if x in string.digits: > print ("string.digits",(x))
Your example works. With range(10) you don't expect to see an "a" either. Thanks -- https://mail.python.org/mailman/listinfo/python-list
