On 2017-08-31 23:30, Chris Angelico wrote: > The method you proposed seems a little odd - it steps through the > strings character by character and casefolds them separately. How is > it superior to the two-line function? And it still doesn't solve any > of your other cases.
It also breaks when casefold() returns multiple characters: >>> s1 = 'ss' >>> s2 = 'SS' >>> s3 = 'ß' >>> equal(s1,s2) # using Steve's equal() function True >>> equal(s1,s3) False >>> equal(s2,s3) False >>> s1.casefold() == s2.casefold() True >>> s1.casefold() == s3.casefold() True >>> s2.casefold() == s3.casefold() True -tkc -- https://mail.python.org/mailman/listinfo/python-list