I have the following line in Python 2:- msgstr = string.join(popmsg[1], "\n") # popmsg[1] is a list containing the lines of the message
... so I changed it to:- s = "\n" msgstr = s.join(popmsg[1]) # popmsg[1] is a list containing the lines of the message However this still doesn't work because popmsg[1] isn't a list of strings, I get the error:- TypeError: sequence item 0: expected str instance, bytes found So how do I do this? I can see clumsy ways by a loop working through the list in popmsg[1] but surely there must be a way that's as neat and elegant as the Python 2 way was? -- Chris Green ยท -- https://mail.python.org/mailman/listinfo/python-list