On 2020-08-26 09:22, Chris Green wrote: > I have the following line in Python 2:- > > msgstr = string.join(popmsg[1], "\n") # popmsg[1] is a list > containing the lines of the message > > ... so I changed it to:- > > s = "\n" > msgstr = s.join(popmsg[1]) # popmsg[1] is a list containing the > lines of the message > > However this still doesn't work because popmsg[1] isn't a list of > strings, I get the error:- > > TypeError: sequence item 0: expected str instance, bytes found > > So how do I do this? I can see clumsy ways by a loop working through > the list in popmsg[1] but surely there must be a way that's as neat > and elegant as the Python 2 way was?
Well, the simple fix is to set s to b"\n" but that may not solve all of your problems. The issue is that popmsg[1] is a list of bytes. You probably want a list of strings. I would look further back and think about getting a list of strings in the first place. Without knowing how popmsg was created we can't tell you how to do that. Of course, if a bytes object is what you want then the above will work. You can also convert to string after the join. Cheers. -- D'Arcy J.M. Cain Vybe Networks Inc. A unit of Excelsior Solutions Corporation - Propelling Business Forward http://www.VybeNetworks.com/ IM:da...@vybenetworks.com VoIP: sip:da...@vybenetworks.com
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