On 2020-08-26 14:22, Chris Green wrote:
I have the following line in Python 2:-
msgstr = string.join(popmsg[1], "\n") # popmsg[1] is a list
containing the lines of the message
... so I changed it to:-
s = "\n"
msgstr = s.join(popmsg[1]) # popmsg[1] is a list containing the lines
of the message
However this still doesn't work because popmsg[1] isn't a list of
strings, I get the error:-
TypeError: sequence item 0: expected str instance, bytes found
So how do I do this? I can see clumsy ways by a loop working through
the list in popmsg[1] but surely there must be a way that's as neat
and elegant as the Python 2 way was?
In Python 3, bytestring literals require the 'b' prefix:
msgstr = b"\n".join(popmsg[1])
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