Found id ! I have to use mapLayerFromString : blayer = QgsProcessingUtils.mapLayerFromString(area_result['OUTPUT'], context)
\o/ 2018-02-16 7:11 GMT+01:00 kimaidou <kimai...@gmail.com>: > Hi Salvatore, > > I already tried to use > > blayer = area_result['OUTPUT'] > for feat in blayer.getFeatures(): > .... > > with no success . If I do so I get > > AttributeError: 'str' object has no attribute 'getFeatures' > > There must be a way to transforme this string representing the layer as a > processing layer object.... > I use this code inside the processAlgorithm method of my > QgsProcessingAlgorithm class. > > > Michaël > > 2018-02-15 22:39 GMT+01:00 Salvatore Larosa <lrssv...@gmail.com>: > >> Hi Michaël, >> >> On Thu, Feb 15, 2018 at 6:36 PM, kimaidou <kimai...@gmail.com> wrote: >> >>> Hi all, >>> >>> I have a simple processing python alg which >>> * generates a buffer with qgis:buffer >>> * use qgis:fieldcalculator to add an buf_area field -> the output vector >>> of my alg is this buffer+new field. >>> >>> I would like to parse the features of the output vector in order to >>> gather some information and put it in a new string output. I have not been >>> able to get the layer object to perform a getFeatures on it. >>> >>> See the code >>> http://paste.debian.net/1010463/ >>> >>> In line 32, my blayer is None >>> I think I am not using the good way to get the output vector layer >>> features? I tried to use the same way as for reading an input layer, but >>> oviously it is different. >>> >> >> What does happen if you put area_result['OUTPUT'] directly instead of >> self.parameterAsSource? >> parameterAsSource() accept a parameter as first argument and area_result >> should be already un QgsVectorLayer. >> >> Where you are trying to execute it from? >> >> >> -- >> Salvatore Larosa >> linkedIn: http://linkedin.com/in/larosasalvatore >> twitter: @lrssvt >> skype: s.larosa >> IRC: lrssvt on freenode >> > >
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