For example:
String xmlString = "<root><stuff arg=\"value\"/></root>";
HttpUtils.Page page = new HttpUtils.Request("http://localhost:8080/
rest")
.postParam("submission", "call")
.postParam("script", xmlString)
.retrieve();
System.out.println(page.getContent());
However, note that this is probably not the most performant, fault-
tolerant, flexible, x, y, z ... way of doing the post request from
the client.
Take care,
Geert
On 21 Dec 2006, at 17:33, Hynek Schlawack wrote:
Geert Bevin <[EMAIL PROTECTED]> writes:
basically, you should create a request like this:
http://localhost:8080/rest?submission=call
but then in post.
I don't know which library you're using, but this is what you'd do
with RIFE's HttpUtils (yes, by just using the RIFE jar in another
application, not necessarily a webapp):
HttpUtils.Page page = new HttpUtils.Request("http://localhost:8080/
rest")
.postParam("submission", "call")
.retrieve();
System.out.println(page.getContent());
I guess the question sounds stupid, but where's the script I want to
submit? I'm pretty baffled through the different possibilities now. %/
I need to submit an XML document, I'd say it's a bad idea to URL
encode
it. %)
--
Geert Bevin
Uwyn "Use what you need" - http://uwyn.com
RIFE Java application framework - http://rifers.org
Music and words - http://gbevin.com
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