I don't think you can copyrigt ideas anyway. Im not an expert on copyright but im pretty sure you can use ideas without it being a derivitive. Like the man said, there are only so many ways to write a loop
If I used for (x=0;x>10;x++) in a program I write and another program does the same, is it a derivitive? I don't think so. I think derivitive would be if you started with ROM and changed it. No matter HOW much you change it's still a derivitive of ROM. Using ideas that you see in another mud such as ROM I don't think counts. As long as you didn't steal the code from it. Not an expert opinion, just mine. I may be 110% wrong. K > -----Original Message----- > From: Jason Gauthier [mailto:[EMAIL PROTECTED] > Sent: Friday, May 16, 2003 2:04 PM > To: '[EMAIL PROTECTED]' > Cc: '[email protected]' > Subject: RE: Requesting help > > > Personally, I wouldn't be over concerned with borrowing a > little socket code > from ROM. > > The 10 lines worth of socket code required can be found on > 100 sites about > socket programming. > It's far from stealing, or borrowing. It's just convenient. > > > -----Original Message----- > > From: Mark Roberts [mailto:[EMAIL PROTECTED] > > Sent: Friday, May 16, 2003 1:56 PM > > To: Pell, Blake > > Cc: [email protected] > > Subject: Re: Requesting help > > > > > > On Friday 16 May 2003 11:58, Pell, Blake wrote: > > >If you are looking, then re-typing the code it might as well > > be copying > > >code at which point I'd think it violates the ROM license > if you're > > >making your own source. > > > > Oh my god, I've had to bite back sooo many biting retorts. > > So, I'll just let the code speak for itself. I'll let the > > list tell me if I have a ROM derivative or not... (but > > really, honestly, I see no way that I can stop it from being > > a ROM derivative if you call it one - there's only so many > > ways to send data in a loop to someone!!) > > > > Really though, of 926 lines of code (real code, non-blank or > > comment), 917 are completely unique. (Or... they better be!) > > > > // Snip. > > const char color_ident[16] = { > > 'x', 'r', 'g', 'y', 'b', 'm', 'c', 'w', 'd', > > 'R', 'G', 'Y', 'B', 'M', 'C', 'W' > > }; > > const char * colors[16] = { > > "\e[0m", "\e[0;31m", "\e[0;32m", "\e0;33m", > > "\e[0;34m", "\e[0;35m", "\e[0;36m", "\e0;37m", > > "\e[1;30m", "\e[1;31m", "\e[1;32m", "\e[1;33m", > > "\e[1;34m", "\e[1;35m", "\e[1;36m", "\e[1;37m" > > }; > > void telnet_server::write_to_descriptor(descriptor * d) > > { > > if (serverdown) > > return; > > string str; > > char input[8192], txt[8192]; > > int start, write, block, x, length; > > str=d->get_outbuf(); > > if (str == "") > > return; > > *input=0; > > strcpy(input, str.c_str()); > > length=strlen(input); > > *txt=0; > > for (start=block=0; start < length; start++) > > { > > if (input[start] == '{') > > { > > if (input[start+1] == color_ident[x]) > > { > > strncat(txt, input+block, start-block); > > strcat(txt, colors[x]); > > block=start+2; > > break; > > } > > } > > } > > strncat(txt, input+block, start-block); > > x=d->get_socket(); > > length=strlen(txt); > > for(start=0; start < length; start+=write) > > { > > block=(length-start < 4096)?length-start:4096; > > if ((write=send(x, txt+start, block, 0)) < 0) > > { > > perror("write_to_descriptor() failed"); > > return; > > } > > } > > } > > > > > > // End snip > > > > I will note, however, that your issue of whether or not it's > > a ROM derivative is... utterly unimportant. I posted to find > > out if I can enlist the aid of someone with skill. Because > > I'm at my wit's end.. I cannot figure out why once everyone > > logs out of the mud, and someone logs back in, the mud > > crashes on the first command they type, and their pretitle is > > mystically "You're all set!" and their name is my room description!! > > > > Oh. Noteworthy: a clean compile didn't fix it... but I hadn't > > tried it. Its much appreciated and will go on my list of > > "things to try before whining" > > > > ;-) Thanks Dale. > > > > Mark > > Esheliam > > > > -- > > -----BEGIN GEEK CODE BLOCK----- > > Version: 3.12 > > GCS d s: a-- C++>$ UL+ P+ L++ !E(---) W- N o? K? w > > O- M-- V-- PS+ PE-- Y+ !PGP !tv t+ 5? X? R* b+++ DI+ D- > > G++ e++> h---- r+++ y-- > > ------END GEEK CODE BLOCK------ > > > > > > > > > > > > -- > > ROM mailing list > > [email protected] > > http://www.rom.org/cgi-bin/mailman/listinfo/rom > > > > -- > ROM mailing list > [email protected] > http://www.rom.org/cgi-bin/mailman/listinfo/rom >
