Anything with @ feels like it goes too close to pointer sigils for my taste.
Patrick
spir <denis.s...@gmail.com> wrote:
>On 12/02/2013 11:57 AM, Kevin Ballard wrote:
>> With @ going away another possibility is to leave ~ as the normal
>allocation operator and to use @ as the placement operator. So ~expr
>stays the same and placement looks either like `@place expr` or
>`expr@place`
>
>I like that, with expr@place. Does this give:
> let foo = ~ bar;
> let placed_foo = bar @ place;
>?
>
>Yet another solution, just for fun, using the fact that pointers are
>supposed to
>"point to":
>
> let foo = -> bar;
> let placed_foo = bar -> place;
>
>Denis
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