Still too punctuation heavy.
Kevin Ballard <[email protected]> wrote:
>What do you mean? This suggestion uses @ as an operator, not as a
>sigil.
>
>-Kevin
>
>On Dec 2, 2013, at 10:23 AM, Patrick Walton <[email protected]>
>wrote:
>
>> Anything with @ feels like it goes too close to pointer sigils for my
>taste.
>>
>> Patrick
>>
>> spir <[email protected]> wrote:
>> On 12/02/2013 11:57 AM, Kevin Ballard wrote:
>> With @ going away another possibility is to leave ~ as the normal
>allocation operator and to use @ as the placement operator. So ~expr
>stays the same and placement looks either like `@place expr` or
>`expr@place`
>>
>> I like that, with expr@place. Does this give:
>> let foo = ~ bar;
>> let placed_foo = bar @ place;
>> ?
>>
>> Yet another solution, just for fun, using the fact that pointers are
>supposed to
>> "point to":
>>
>> let foo = -> bar;
>> let placed_foo = bar -> place;
>>
>> Denis
>>
>> Rust-dev mailing list
>> [email protected]
>> https://mail.mozilla.org/listinfo/rust-dev
>>
>> --
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