What do you mean? This suggestion uses @ as an operator, not as a sigil. -Kevin
On Dec 2, 2013, at 10:23 AM, Patrick Walton <pwal...@mozilla.com> wrote: > Anything with @ feels like it goes too close to pointer sigils for my taste. > > Patrick > > spir <denis.s...@gmail.com> wrote: > On 12/02/2013 11:57 AM, Kevin Ballard wrote: > With @ going away another possibility is to leave ~ as the normal allocation > operator and to use @ as the placement operator. So ~expr stays the same and > placement looks either like `@place expr` or `expr@place` > > I like that, with expr@place. Does this give: > let foo = ~ bar; > let placed_foo = bar @ place; > ? > > Yet another solution, just for fun, using the fact that pointers are supposed > to > "point to": > > let foo = -> bar; > let placed_foo = bar -> place; > > Denis > > Rust-dev mailing list > Rust-dev@mozilla.org > https://mail.mozilla.org/listinfo/rust-dev > > -- > Sent from my Android phone with K-9 Mail. Please excuse my brevity. > _______________________________________________ > Rust-dev mailing list > Rust-dev@mozilla.org > https://mail.mozilla.org/listinfo/rust-dev
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