> For people interested in helping out, a few words about integration is
> in order. As we discussed on this list before, many problems in
> integration can be handled with heuristics before calling more advanced
> algorithms. The heuristics also give more user friendly answers in most
> cases.
>
> Integration code in Sage should run through some preprocessing before
> calling anything else, be it maxima, or a native implementation of the
> Risch algorithm.
>
> There are some links to descriptions of heuristics used by maxima and maple 
> at this page:
>
> http://wiki.sagemath.org/symbolics
>
> Pattern matching and rewriting capabilities of the new symbolics will
> be very useful for this. Anybody interested in improving the
> integration capabilities of Sage can help, no high level mathematical
> knowledge is necessary.
>

This is very interesting, indeed I have no high level mathematical
knowledge :)

Just for fun, I was trying to implement the most basic examples (1.4
and 1.5) of this page, linked in the wiki:
http://www.cs.uwaterloo.ca/~kogeddes/papers/Integration/IntSurvey.html

Let me make this straight: I have not understood what is intended to
be a resultant() and I have absolutely no experience with rings nor
with multivariate polynomials. Nonetheless, I tried this code in SAGE:

reset()
P.<x,y,z> = PolynomialRing(QQ)
# P.<x,y,z> = GF(5)[]

A = -1
B = x^3 + x
tores = A - z*B.derivative(x)
res = tores.resultant(B,x); factor(res)

I get:
(-1) * (z + 1) * (2*z - 1)^2

That is somehow close to the result shown in the link, but why is it
not identical?

Moreover, why if I use the second statement (the one in the comment)
to define the ring, do I get a completely different answer? E.g.:
(z + 1) * (z + 2)^2

Which is the correct way to define the ring in this case?

Finally, even assuming that I can get the right answer from this,
which is the recommended way to get the roots of an equation given by
a "univariate polynomials == 0"? This is supposed to be the next step
of the algorithm.

The worst way I can think of is to use repr(), so that I can use solve
(), but hopefully there's a better way, at least to convert a
polynomials to a symbolic expression... Is there?

I know this is not leading anywhere... but thank you for your time! :)

Regards

Maurizio
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