Hi,
On Tue, Aug 18, 2009 at 8:42 PM, rjf<fate...@gmail.com> wrote:
>
> did you mean to integrate with respect to "x^2" ?
Yes.
> Well, x^2 doesn't occur in f(x). So let's rename x^2 as y.
> What is the integral of f(x) with respect to y?
>
> It is y*f(x).
>
> substituting back x^2 for y, you get x^2*f(x).
Are you saying during integration maxima is not aware
that "x^2" is the square of "x"?
Take following examples:
----------
(%i4) integrate(log(x), x);
(%o4) x log(x) - x
(%i5) integrate(log(x^2), x^2);
2
(%o5) 2 x log(x)
----------
"log" is certainly aware of it.
> Certainly Maxima expects "the variable of integration" as
> the second argument. Anything else is asking for trouble.
Then maxima should throw error instead of giving a wrong
answer silently. This is rather bizarre given maxima is known
to be over-cautious during integration and sometime
it asks too many questions, even something like
--------
(%i6) integrate(1/x, x, 0, 1);
Is x + 1 positive, negative, or zero?
--------
Cheers,
Golam
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