On 2014-11-19 9:36 AM, "Bill Page" <bill.p...@newsynthesis.org> wrote:
> ...
> Then I noticed that if we have f=z we get
>
>   conjugate(z).diff(z)
>
> which is 0.  So the 2nd term is 0 and the result is just the first
Wirtinger derivative.
>
> Perhaps I am misinterpreting something?
>

Oops, my fault.  According to your definition

  conjugate(z).diff(z) = 1

Bill.

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