On Wed, Nov 19, 2014 at 8:19 AM, Bill Page <bill.p...@newsynthesis.org> wrote:
>
> On 2014-11-19 9:36 AM, "Bill Page" <bill.p...@newsynthesis.org> wrote:
>> ...
>> Then I noticed that if we have f=z we get
>>
>> conjugate(z).diff(z)
>>
>> which is 0. So the 2nd term is 0 and the result is just the first
>> Wirtinger derivative.
>>
>> Perhaps I am misinterpreting something?
>>
>
> Oops, my fault. According to your definition
>
> conjugate(z).diff(z) = 1
Right, because this "diff" is the total derivative in the direction
theta, so the first Wirtinger derivative is 0, the second one is 1 and
you get:
0 + 1*e^{-2*i*theta})
and if you implicitly set theta=0, then you get 1.
Ondrej
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