Dear support, sage: find_root(.05^(x+1)==(x+1)*10^(-10),5,100)
yields DeprecationWarning: Substitution using function-call syntax and unnamed arguments is deprecated and will be removed from a future release of Sage; you can use named arguments instead, like EXPR(x=..., y=...) But I didn't actually do anything like sage: f=x^2 sage: f(2) Is there something internal to find_root that does this, or should there be different syntax? find_root? says a symbolic equality is ok for input, and nothing about deprecation. It would indeed be tedious to have to define a polynomial ring just to do this computation. Thanks! - kcrisman --~--~---------~--~----~------------~-------~--~----~ To post to this group, send email to sage-support@googlegroups.com To unsubscribe from this group, send email to sage-support-unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sage-support URLs: http://www.sagemath.org -~----------~----~----~----~------~----~------~--~---
