That would require a change in the moveCodeToImg function. A naive
example would be:
function moveCodeToImg(element) {
// Catch $().each() calls of the function
if (typeof element == 'number') element = this;
// do stuff to element
}
-blair
Abel Tamayo wrote:
> Wow, thanks everyone
Each takes a function as a parameter. Generally people just pass in an
anonymous function (e.g. $('.oneclass').each(function(i) {}); ) but there is
no reason you can't pass in a function you defined previously (e.g.
$('.oneclass').each(fmoveCodeToImg); ).
So, each has a function. When it runs, it
Wow, thanks everyone for the superfast response.
Ok, as Brandon suggested, the right way was using
$('.oneClass').each(function() { moveCodeToImg(this); });
wich I had already tried but didn't realize i had to change some things in
the function used since i was recycling it and the parameters an
On 12/18/06, Mike Alsup <[EMAIL PROTECTED]> wrote:
> > shouldn't be called. You could write it like this:
> >
> > $('.oneClass').each(function() { moveCodeToImg(this); });
>
> I was thinking of this:
>
> $('.oneClass').each(moveCodeToImg);
Indeed, it would be cleaner ... just make sure the moveCod
On 12/18/06, Brandon Aaron <[EMAIL PROTECTED]> wrote:
To just expound on what Mike mentioned ... by saying,
'moveCodeToImg(this)' you are trying to call a function where it
shouldn't be called. You could write it like this:
$('.oneClass').each(function() { moveCodeToImg(this); });
pffft...sho
> shouldn't be called. You could write it like this:
>
> $('.oneClass').each(function() { moveCodeToImg(this); });
I was thinking of this:
$('.oneClass').each(moveCodeToImg);
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Can you give any more details on the exception? (file, line number, etc).
Perhaps a link to the page you're working on as well?
Inside each(), "this" is a DOM object (which ever one is currently being
iterated over), so I believe your code should work.
On 12/18/06, Abel Tamayo <[EMAIL PROTECTED
On 12/18/06, Abel Tamayo <[EMAIL PROTECTED]> wrote:
> $(".oneClass").each(moveCodeToImg(this))
To just expound on what Mike mentioned ... by saying,
'moveCodeToImg(this)' you are trying to call a function where it
shouldn't be called. You could write it like this:
$('.oneClass').each(function() {
> $(".oneClass").each(moveCodeToImg(this))
Don't try to pass 'this' into the function. It will be set for you.
The arg passed into your function will actually be an index.
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Alright. I have a non Jquery function called myFunction(domObject) prepared
to receive a DOM object as a parameter.
I want to use this function with several objects that share the same class,
so i use a sentence like this in the main page:
$(".oneClass").each(moveCodeToImg(this))
, but it doesn'
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