Thanks Christian and Robert,
I took Christian's advice and was able to get the render order (by looking at
the bin number) of each node that was hit and just return the node with the
highest render order.
I didn't attempt incorporating the z buffer. Seemed a little over my head.
Thanks so
Hello,
Note the inclusion of your favorite open source system in the list of topics…J
Deadline Extended again……
Summersim’15 final call for papers.
DEADLINE EXTENDED to March 20, 2015.
Notification: April 20, 2015
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First, the Computer Graphics Paper track
Hi Robert,
works perfectly as can be seen:
http://cdash.openscenegraph.org/index.php?project=OpenSceneGraphdate=2015-03-04
thanks
Mattias
On Tue, Mar 3, 2015 at 1:02 PM, Robert Osfield robert.osfi...@gmail.com wrote:
Hi Mattias,
It looks like a revision to the PolygonMode.cpp to better
Your remote display problem is a limitation of Windows Remote Desktop's OpenGL
support. There are three potential solutions:
1) Only use OpenGL 1.1 features if you're using remote desktop - not very
practical possibly not even possible with OpenSceneGraph.
2) Use ANGLE and OpenGL ES - Angle is
Hi Alistair,
Thanks for your details answer. I will try option 3. Thanks.
Regards,
Clement
From: osg-users [osg-users-boun...@lists.openscenegraph.org] on behalf of
Alistair Baxter [alist...@mve.com]
Sent: Wednesday, 4 March 2015 21:50
To:
Hi Alistair,
I forgot to ask a question. Remote desktop works on the machine which has
Nivida Quadro display card installed. Do you know why it works probably?
Regards,
Clement
From: osg-users [osg-users-boun...@lists.openscenegraph.org] on
If you mean, why does it work if the program is started before connecting,
then it's to do with the way Windows controls access to its graphics hardware.
Microsoft could probably have fixed it, but they have chosen not to, and so we
have to live with working around it.
-Original
Hi Robert,
If I put a complex version line line
#version 400 compatibility
at the beginning of my shader's source a non-valid shader code is produced.
I've dived into the problem and found that finding the end line
terminator is non-robust in this case.
It determines the line's end with
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