Re: [algogeeks] DP problems

2014-06-05 Thread Shashwat Anand
I am not too sure about your O (N^3) solution even.  Can you link the
working code ?


On Thu, Jun 5, 2014 at 6:48 PM, kumar raja rajkumar.cs...@gmail.com wrote:

 This is a very good collection of DP problems.

 I want the answers for problem 2(e)
 and problem 14.

 for problem 14 the recurrence relation
 that i have is

 T[i,j] = 0 if i=j
1 if j=i+1 and s[i]=s[j]
0 if j=i+1 and s[i]!=s[j]
j-i+1/2 if s[i..j] is even length palindrome
j-i/2  if s[i..j] is odd length palindrome
max{T[i+1,j],T[i,j-1]} else

 But this is O(n^3) solution. Could not
 find out solution of order O(n^2).
 If someone knows please share the answers for them.


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Re: [algogeeks] DP problems

2014-06-05 Thread kumar raja
U have two dimensions for the table ( has O(n^2) entries.) and to check
whether string is palindrome or not it will take O(n) . So it is O(n^3)
solution.

I have checked it manually for some inputs, and it works.


On 5 June 2014 18:53, Shashwat Anand m...@shashwat.me wrote:

 I am not too sure about your O (N^3) solution even.  Can you link the
 working code ?


 On Thu, Jun 5, 2014 at 6:48 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 This is a very good collection of DP problems.

 I want the answers for problem 2(e)
 and problem 14.

 for problem 14 the recurrence relation
 that i have is

 T[i,j] = 0 if i=j
1 if j=i+1 and s[i]=s[j]
0 if j=i+1 and s[i]!=s[j]
j-i+1/2 if s[i..j] is even length palindrome
j-i/2  if s[i..j] is odd length palindrome
max{T[i+1,j],T[i,j-1]} else

 But this is O(n^3) solution. Could not
 find out solution of order O(n^2).
 If someone knows please share the answers for them.


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Re: [algogeeks] DP problems

2014-06-05 Thread Shashwat Anand
Code ?


On Thu, Jun 5, 2014 at 7:08 PM, kumar raja rajkumar.cs...@gmail.com wrote:

 U have two dimensions for the table ( has O(n^2) entries.) and to check
 whether string is palindrome or not it will take O(n) . So it is O(n^3)
 solution.

 I have checked it manually for some inputs, and it works.


 On 5 June 2014 18:53, Shashwat Anand m...@shashwat.me wrote:

 I am not too sure about your O (N^3) solution even.  Can you link the
 working code ?


 On Thu, Jun 5, 2014 at 6:48 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 This is a very good collection of DP problems.

 I want the answers for problem 2(e)
 and problem 14.

 for problem 14 the recurrence relation
 that i have is

 T[i,j] = 0 if i=j
1 if j=i+1 and s[i]=s[j]
0 if j=i+1 and s[i]!=s[j]
j-i+1/2 if s[i..j] is even length palindrome
j-i/2  if s[i..j] is odd length palindrome
max{T[i+1,j],T[i,j-1]} else

 But this is O(n^3) solution. Could not
 find out solution of order O(n^2).
 If someone knows please share the answers for them.


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Re: [algogeeks] DP problems

2014-06-05 Thread Saurabh Paliwal
Hi all!
Well, I agree with Shashwat in that Kumar is wrong with his solution. For
example a string  kumarxyzramuk  will tell you why.
I have a solution which runs in O(n*n) time. It is top-down dynamic
programming approach. Let me know if you don't understand something or if
there is some glitch in the solution. I think it is correct.

Link to the C++ code  - http://ideone.com/Qzs990


On Thu, Jun 5, 2014 at 7:13 PM, Shashwat Anand m...@shashwat.me wrote:

 Code ?


 On Thu, Jun 5, 2014 at 7:08 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 U have two dimensions for the table ( has O(n^2) entries.) and to check
 whether string is palindrome or not it will take O(n) . So it is O(n^3)
 solution.

 I have checked it manually for some inputs, and it works.


 On 5 June 2014 18:53, Shashwat Anand m...@shashwat.me wrote:

 I am not too sure about your O (N^3) solution even.  Can you link the
 working code ?


 On Thu, Jun 5, 2014 at 6:48 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 This is a very good collection of DP problems.

 I want the answers for problem 2(e)
 and problem 14.

 for problem 14 the recurrence relation
 that i have is

 T[i,j] = 0 if i=j
1 if j=i+1 and s[i]=s[j]
0 if j=i+1 and s[i]!=s[j]
j-i+1/2 if s[i..j] is even length palindrome
j-i/2  if s[i..j] is odd length palindrome
max{T[i+1,j],T[i,j-1]} else

 But this is O(n^3) solution. Could not
 find out solution of order O(n^2).
 If someone knows please share the answers for them.


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   B-Tech. Comp. Science and Engg.

   IIT ROORKEE

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Re: [algogeeks] DP problems

2014-06-05 Thread kumar raja
Yes i agree that my recurrence relation is wrong. I have checked it some
inputs, it did not work. But i think the brute force solution is possible
in O(n^3) solution. We have O(n^2) combination of end points. we can check
for the maximum possible even length palin string in O(n). So that will
give O(n^3). Anyone has solution about O(n^2)?


On 5 June 2014 22:25, Saurabh Paliwal saurabh.paliwa...@gmail.com wrote:

 Hi all!
 Well, I agree with Shashwat in that Kumar is wrong with his solution. For
 example a string  kumarxyzramuk  will tell you why.
 I have a solution which runs in O(n*n) time. It is top-down dynamic
 programming approach. Let me know if you don't understand something or if
 there is some glitch in the solution. I think it is correct.

 Link to the C++ code  - http://ideone.com/Qzs990


 On Thu, Jun 5, 2014 at 7:13 PM, Shashwat Anand m...@shashwat.me wrote:

 Code ?


 On Thu, Jun 5, 2014 at 7:08 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 U have two dimensions for the table ( has O(n^2) entries.) and to check
 whether string is palindrome or not it will take O(n) . So it is O(n^3)
 solution.

 I have checked it manually for some inputs, and it works.


 On 5 June 2014 18:53, Shashwat Anand m...@shashwat.me wrote:

 I am not too sure about your O (N^3) solution even.  Can you link the
 working code ?


 On Thu, Jun 5, 2014 at 6:48 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 This is a very good collection of DP problems.

 I want the answers for problem 2(e)
 and problem 14.

 for problem 14 the recurrence relation
 that i have is

 T[i,j] = 0 if i=j
1 if j=i+1 and s[i]=s[j]
0 if j=i+1 and s[i]!=s[j]
j-i+1/2 if s[i..j] is even length palindrome
j-i/2  if s[i..j] is odd length palindrome
max{T[i+1,j],T[i,j-1]} else

 But this is O(n^3) solution. Could not
 find out solution of order O(n^2).
 If someone knows please share the answers for them.


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IIT ROORKEE

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Re: [algogeeks] DP problems

2014-06-05 Thread Saurabh Paliwal
Dude! That is what I just posted. Also your logic is wrong, Palindrome
thing is just not working. Think for a while on this problem.


On Thu, Jun 5, 2014 at 11:18 PM, kumar raja rajkumar.cs...@gmail.com
wrote:

 Yes i agree that my recurrence relation is wrong. I have checked it some
 inputs, it did not work. But i think the brute force solution is possible
 in O(n^3) solution. We have O(n^2) combination of end points. we can check
 for the maximum possible even length palin string in O(n). So that will
 give O(n^3). Anyone has solution about O(n^2)?


 On 5 June 2014 22:25, Saurabh Paliwal saurabh.paliwa...@gmail.com wrote:

 Hi all!
 Well, I agree with Shashwat in that Kumar is wrong with his solution. For
 example a string  kumarxyzramuk  will tell you why.
 I have a solution which runs in O(n*n) time. It is top-down dynamic
 programming approach. Let me know if you don't understand something or if
 there is some glitch in the solution. I think it is correct.

 Link to the C++ code  - http://ideone.com/Qzs990


 On Thu, Jun 5, 2014 at 7:13 PM, Shashwat Anand m...@shashwat.me wrote:

 Code ?


 On Thu, Jun 5, 2014 at 7:08 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 U have two dimensions for the table ( has O(n^2) entries.) and to check
 whether string is palindrome or not it will take O(n) . So it is O(n^3)
 solution.

 I have checked it manually for some inputs, and it works.


 On 5 June 2014 18:53, Shashwat Anand m...@shashwat.me wrote:

 I am not too sure about your O (N^3) solution even.  Can you link the
 working code ?


 On Thu, Jun 5, 2014 at 6:48 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 This is a very good collection of DP problems.

 I want the answers for problem 2(e)
 and problem 14.

 for problem 14 the recurrence relation
 that i have is

 T[i,j] = 0 if i=j
1 if j=i+1 and s[i]=s[j]
0 if j=i+1 and s[i]!=s[j]
j-i+1/2 if s[i..j] is even length palindrome
j-i/2  if s[i..j] is odd length palindrome
max{T[i+1,j],T[i,j-1]} else

 But this is O(n^3) solution. Could not
 find out solution of order O(n^2).
 If someone knows please share the answers for them.


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Re: [algogeeks] DP problems

2014-06-05 Thread kumar raja
U need not get an exact palindrome. u will start comparing from both the
end points till they are equal and does not cross each other. So that
should be possible in linear time right. I did not get ur code exactly and
u have written O(n*n) so i have got the doubt.


On 5 June 2014 23:22, Saurabh Paliwal saurabh.paliwa...@gmail.com wrote:

 Dude! That is what I just posted. Also your logic is wrong, Palindrome
 thing is just not working. Think for a while on this problem.


 On Thu, Jun 5, 2014 at 11:18 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 Yes i agree that my recurrence relation is wrong. I have checked it some
 inputs, it did not work. But i think the brute force solution is possible
 in O(n^3) solution. We have O(n^2) combination of end points. we can check
 for the maximum possible even length palin string in O(n). So that will
 give O(n^3). Anyone has solution about O(n^2)?


 On 5 June 2014 22:25, Saurabh Paliwal saurabh.paliwa...@gmail.com
 wrote:

 Hi all!
 Well, I agree with Shashwat in that Kumar is wrong with his solution.
 For example a string  kumarxyzramuk  will tell you why.
 I have a solution which runs in O(n*n) time. It is top-down dynamic
 programming approach. Let me know if you don't understand something or if
 there is some glitch in the solution. I think it is correct.

 Link to the C++ code  - http://ideone.com/Qzs990


 On Thu, Jun 5, 2014 at 7:13 PM, Shashwat Anand m...@shashwat.me wrote:

 Code ?


 On Thu, Jun 5, 2014 at 7:08 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 U have two dimensions for the table ( has O(n^2) entries.) and to
 check whether string is palindrome or not it will take O(n) . So it is
 O(n^3) solution.

 I have checked it manually for some inputs, and it works.


 On 5 June 2014 18:53, Shashwat Anand m...@shashwat.me wrote:

 I am not too sure about your O (N^3) solution even.  Can you link the
 working code ?


 On Thu, Jun 5, 2014 at 6:48 PM, kumar raja rajkumar.cs...@gmail.com
 wrote:

 This is a very good collection of DP problems.

 I want the answers for problem 2(e)
 and problem 14.

 for problem 14 the recurrence relation
 that i have is

 T[i,j] = 0 if i=j
1 if j=i+1 and s[i]=s[j]
0 if j=i+1 and s[i]!=s[j]
j-i+1/2 if s[i..j] is even length palindrome
j-i/2  if s[i..j] is odd length palindrome
max{T[i+1,j],T[i,j-1]} else

 But this is O(n^3) solution. Could not
 find out solution of order O(n^2).
 If someone knows please share the answers for them.


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Re: [algogeeks] DP problems

2014-06-05 Thread Saurabh Paliwal
Ok! So I guess now we are talkng my solution. What i do is maintain two
pointers i and j, i is the end of the first string and j is the beginning
of the second. If both the character match, I calculate the answer for
pointers i-1,j+1 and add 1 to the answer for i,j. If they don't match, I
simply mark 0 as the answer for i,j. So my table if filled top-down like
this. Finally, I return the maximum entry in the table.
Need I explain further? If so, feel free. Should I explain what those
methods do?

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Re: [algogeeks] DP problems

2014-06-05 Thread Saurabh Paliwal
And now I get what you meant when you said palindrome. You should have
explained that if that was not exact palindrome

So yes, your solution seems correct but that is the brute force approach.
It runs in O(n*n*n) as there are n*n substrings and every check is linear.
DP solution helps save time by memoization.


On Thu, Jun 5, 2014 at 11:37 PM, Saurabh Paliwal 
saurabh.paliwa...@gmail.com wrote:

 Ok! So I guess now we are talkng my solution. What i do is maintain two
 pointers i and j, i is the end of the first string and j is the beginning
 of the second. If both the character match, I calculate the answer for
 pointers i-1,j+1 and add 1 to the answer for i,j. If they don't match, I
 simply mark 0 as the answer for i,j. So my table if filled top-down like
 this. Finally, I return the maximum entry in the table.
 Need I explain further? If so, feel free. Should I explain what those
 methods do?




-- 
 -Saurabh Paliwal

   B-Tech. Comp. Science and Engg.

   IIT ROORKEE

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Re: [algogeeks] DP problems

2014-06-05 Thread kumar raja
If i get u correctly, this is the recurrence relation ( i feel this makes
many people to understand the solution rather than looking at the code)


T[i..j] indicates the length of longest even length palin string ( not
exactly palin but i think u know what i am saying) with i as begin and j as
ending point.

T[i,j] = 0 if i=j
   T[i+1,j-1]+1 if s[i]==s[j]
  0else

And u find max value in the table which is the answer

So time complexity  = space complexity = O(n^2).

Correct me if i am wrong



On 5 June 2014 23:44, Saurabh Paliwal saurabh.paliwa...@gmail.com wrote:

 And now I get what you meant when you said palindrome. You should have
 explained that if that was not exact palindrome

 So yes, your solution seems correct but that is the brute force approach.
 It runs in O(n*n*n) as there are n*n substrings and every check is linear.
 DP solution helps save time by memoization.


 On Thu, Jun 5, 2014 at 11:37 PM, Saurabh Paliwal 
 saurabh.paliwa...@gmail.com wrote:

 Ok! So I guess now we are talkng my solution. What i do is maintain two
 pointers i and j, i is the end of the first string and j is the beginning
 of the second. If both the character match, I calculate the answer for
 pointers i-1,j+1 and add 1 to the answer for i,j. If they don't match, I
 simply mark 0 as the answer for i,j. So my table if filled top-down like
 this. Finally, I return the maximum entry in the table.
 Need I explain further? If so, feel free. Should I explain what those
 methods do?




 --
  -Saurabh Paliwal

B-Tech. Comp. Science and Engg.

IIT ROORKEE

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Re: [algogeeks] DP problems

2014-06-05 Thread Saurabh Paliwal
T[i][j] = 0 (i  0 || j =n || i = j || s[i] != s[j])

T[i][j] = 1 + T[i-1][j+1]




On Fri, Jun 6, 2014 at 12:19 AM, kumar raja rajkumar.cs...@gmail.com
wrote:

 If i get u correctly, this is the recurrence relation ( i feel this makes
 many people to understand the solution rather than looking at the code)


 T[i..j] indicates the length of longest even length palin string ( not
 exactly palin but i think u know what i am saying) with i as begin and j as
 ending point.

 T[i,j] = 0 if i=j
T[i+1,j-1]+1 if s[i]==s[j]
   0else

 And u find max value in the table which is the answer

 So time complexity  = space complexity = O(n^2).

 Correct me if i am wrong



 On 5 June 2014 23:44, Saurabh Paliwal saurabh.paliwa...@gmail.com wrote:

 And now I get what you meant when you said palindrome. You should have
 explained that if that was not exact palindrome

 So yes, your solution seems correct but that is the brute force approach.
 It runs in O(n*n*n) as there are n*n substrings and every check is linear.
 DP solution helps save time by memoization.


 On Thu, Jun 5, 2014 at 11:37 PM, Saurabh Paliwal 
 saurabh.paliwa...@gmail.com wrote:

 Ok! So I guess now we are talkng my solution. What i do is maintain two
 pointers i and j, i is the end of the first string and j is the beginning
 of the second. If both the character match, I calculate the answer for
 pointers i-1,j+1 and add 1 to the answer for i,j. If they don't match, I
 simply mark 0 as the answer for i,j. So my table if filled top-down like
 this. Finally, I return the maximum entry in the table.
 Need I explain further? If so, feel free. Should I explain what those
 methods do?




 --
  -Saurabh Paliwal

B-Tech. Comp. Science and Engg.

IIT ROORKEE

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 -Saurabh Paliwal

   B-Tech. Comp. Science and Engg.

   IIT ROORKEE

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